31 Javascript Regex With Variable

str1 = "pattern" var re = new RegExp (str1, "g"); "pattern matching .".replace (re, "regex"); click below button to copy the code. By JavaScript tutorial team. This yields "regex matching ." . However, it will fail if str1 is ".". we'd expect the result to be "pattern matching regex", replacing the period with "regex… 2/12/2019 · The right way of doing it is by using a regular expression constructor new RegExp (). const str = "Hello yes what are you yes doing yes" const removeStr = "yes" //variable const regex = new RegExp(removeStr,'g'); // correct way const newstr = str.replace(regex,''); // it works.

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25/3/2012 · But that doesn't mean there is no way to pass variables to a regular experssion in JavaScript. Enter the RegExp class: var re = new RegExp (replacee); sentence.replace (re, replacer); // "Regular Expreshun". Yay! So it looks like we can very well use variables with Regular Expressions.

Javascript regex with variable. To build a regular expression from a variable in JavaScript, you'll need to use the RegExp constructor with a string parameter. function reg(input) { var flags; //could be any combination of 'g', 'i', and 'm' flags = 'g'; return new RegExp('ReGeX' + input + 'ReGeX', flags); } 23/7/2021 · We can use the JavaScript RegExp Object for creating a regex pattern from a dynamic string. Here is the solution for you: var dynamicPart = "XYZ"; // \074 is code for < and \076 is code for > var regexObj = new RegExp("\074" + dynamicPart + "\076"); // will match <XYZ> // the line above is same as, var regex = /\074abc\076/; var input = "<XYZ> Some text </XYZ>"; var output = …

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